Question 46: Wave Optics

Question

In Young's double slit experiment with sodium vapour lamp of wavelength 589 nm and slit 0.589 mm apart, the half angular width of the central maxima is

Accepted Answer

Given, $$\lambda$$ = 589 nm = 589 $$	imes$$ 10$$^{-9}$$ m
d = 0.589 mm = 0.589 $$	imes$$ 10$$^{-3}$$ m
In Young's double slit experiment, half angular width of central maxima is
$$\sin 	heta  = {\lambda  \over d} = {{589 	imes {{10}^{ - 9}}} \over {0.589 	imes {{10}^{ - 3}}}} = {10^{ - 3}} \Rightarrow 	heta  = {\sin ^{ - 1}}(0.001)$$

Answer

$${\sin ^{ - 1}}(0.01)$$

Answer

$${\sin ^{ - 1}}(0.0001)$$

Answer

$${\sin ^{ - 1}}(0.001)$$

Answer

$${\sin ^{ - 1}}(0.1)$$

Wave Optics

In Young's double slit experiment with sodium vapour lamp of wavelength 589 nm and slit 0.589 mm apart, the half angular width of the central maxima is

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