Question 383: Thermodynamics & KTG

Question

When M
1
gram of ice at –10
o
C (specific heat = 0.5 cal g
–1
o
C
–1
) is added to M
2
gram of water at 50C, finally
no ice is left and the water is at 0°C. The value of latent heat of ice, in cal g
–1
is :

Accepted Answer

Heat lost = Heat gain
$$ \Rightarrow {M_2} 	imes 1 	imes 50 = {M_1} 	imes 0.5 	imes 10 + {M_1}.{L_f}$$
$$ \Rightarrow {L_f} = {{50{M_2} - 5{M_1}} \over {{M_1}}}$$
$$ = {{50{M_2}} \over {{M_1}}} - 5$$

Answer

$${{50{M_2}} \over {{M_1}}} - 5$$

Answer

$${{50{M_2}} \over {{M_1}}}$$

Answer

$${{5{M_2}} \over {{M_1}}} - 5$$

Answer

$${{5{M_1}} \over {{M_2}}} - 50$$

Thermodynamics & KTG

When M 1 gram of ice at –10 o C (specific heat = 0.5 cal g –1 o C –1 ) is added to M 2 gram of water at 50C, finally no ice is left and the water is at 0°C. The value of latent heat of ice, in cal g –1 is :

Choose the correct answer: