Question 384: Thermodynamics & KTG

Question

A sample of an ideal gas is taken through the cyclic process abca as shown in the figure. The change in the
internal energy of the gas along the path ca is –180 J. The gas absorbs 250 J of heat along the path ab and 60
J along the path bc. The work done by the gas along the path abc is:

Accepted Answer

For the process (c Ã¢ÂÂ a), $$\Delta $$U
ca
= Ã¢ÂÂ 180 J
For process (b Ã¢ÂÂ c) $$ 	o $$ Isochoric (W
bc
= 0)
$$ 	herefore \Delta $$U = 60 J
Heat absorbs along (a Ã¢ÂÂ b), Q
ab
= 250 J
Also $$ 	herefore \Delta$$ U
cycle
= 0
$$ 	herefore \Delta$$  U
ab
= 120 J
So W
a $$ 	o $$ b
= 130 J
Total work done from (a $$ 	o $$ b $$ 	o $$ c)
= W
ab
+ W
bc
= 130 J

Answer

120 J

Answer

130 J

Answer

100 J

Answer

140 J

Thermodynamics & KTG

A sample of an ideal gas is taken through the cyclic process abca as shown in the figure. The change in the internal energy of the gas along the path ca is –180 J. The gas absorbs 250 J of heat along the path ab and 60 J along the path bc. The work done by the gas along the path abc is:

Choose the correct answer: