Question 226: EM waves

Question

If the magnetic field in plane electromagnetic wave is
$$ \mathbf{B}=3 	imes 10^{-8} \sin \left(1.6 	imes 10^3 x+48 	imes 10^{10} tight) \hat{\mathbf{j}} \mathrm{T}, $$
then find the expression of electric field?

Accepted Answer

$$ 	ext { } \begin{aligned} \omega & =48 	imes 10^{10} \ k & =1.6 	imes 10^3 \ V & =\frac{\omega}{k}=\frac{48 	imes 10^{10}}{1.6 	imes 10^3}=30 	imes 10^7 \ & =3 	imes 10^8=c \ B_0 & =\frac{E_0}{c} \ E_0 & =B_0 c=3 	imes 10^{-8} 	imes 3 	imes 10^8\left(\because B_0=3 	imes 10^{-8}ight) \ & =9 \end{aligned} $$
So, expression for $E$
$$ E=9 \sin \left(48 	imes 10^{10} t+1.6 	imes 10^3 xight) $$
Since, magnetic field $B$ is in $y$-direction and propagation vector $k$ in
$x$-direction. So, electric field is to be in $z$-direction.
So, option (c) is correct.

Answer

$60 \sin \left(1.6 	imes 10^3 x+48 	imes 10^{10} tight) \hat{\mathbf{k}} \mathrm{V} / \mathrm{m}$

Answer

$3 	imes 10^{-8} \sin \left(1.6 	imes 10^3 x+48 	imes 10^{10} tight) \hat{\mathrm{i}} \mathrm{V} / \mathrm{m}$

Answer

$9 \sin \left(1.6 	imes 10^3 x+48 	imes 10^{10} tight) \hat{\mathbf{k}} \mathrm{V} / \mathrm{m}$

Answer

$3 	imes 10^{-8} \sin \left(1.6 	imes 10^3 x+48 	imes 10^{10} tight) \hat{\mathbf{j}} \mathrm{V} / \mathrm{m}$

EM waves

If the magnetic field in plane electromagnetic wave is $ \mathbf{B}=3 \times 10^{-8} \sin \left(1.6 \times 10^3 x+48 \times 10^{10} t\right) \hat{\mathbf{j}} \mathrm{T}, $ then find the expression of electric field?

Choose the correct answer: