Question 72: EM waves

Question

The ratio of average electric energy density and total average energy density of electromagnetic wave is :

Accepted Answer

Avg electric energy density $=\frac{1}{4} \varepsilon_0 \mathrm{E}_0^2$
Total Avg energy density $=\frac{1}{2} \varepsilon_0 \mathrm{E}_0^2$
$$ 	herefore $$ Ratio of average electric energy density and total Avg energy density
$$
= \frac{\frac{1}{4} \varepsilon_0 \mathrm{E}_0^2}{\frac{1}{2} \varepsilon_0 \mathrm{E}_0^2}=\frac{2}{4}=\frac{1}{2}
$$

Answer

1

Answer

3

Answer

2

Answer

$$\frac{1}{2}$$

EM waves

The ratio of average electric energy density and total average energy density of electromagnetic wave is :

Choose the correct answer: