Question 39: EM waves

Question

The unit of $\sqrt{\frac{2I}{\varepsilon_0 c}}$ is :
(I = intensity of an electromagnetic wave, c = speed of light)

Accepted Answer

The unit of the expression $\sqrt{\frac{2I}{\varepsilon_0 c}}$ can be determined by exploring the relationship between intensity ($I$) and the electric field ($E_0$) in an electromagnetic wave.
The intensity of an electromagnetic wave is given by:
$ I = \frac{1}{2} \varepsilon_0 E_0^2 	imes c $
From this equation, we can solve for the electric field $E_0$:
$ E_0 = \sqrt{\frac{2I}{\varepsilon_0 c}} $
The symbol $E_0$ represents the electric field, which is measured in units of Newtons per Coulomb (N/C). Therefore, the unit of the expression $\sqrt{\frac{2I}{\varepsilon_0 c}}$ is also $N/C$.
Thus, the expression $\sqrt{\frac{2I}{\varepsilon_0 c}}$ has units of $N/C$.

Answer

Vm

Answer

NC
-1

Answer

NC

Answer

Nm

EM waves

The unit of \sqrt{\frac{2I}{\varepsilon_0 c}} is : (I = intensity of an electromagnetic wave, c = speed of light)

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