Question 151: EM waves

Question

Magnetic field in a plane electromagnetic wave is given by
$\overrightarrow B $ = B
0
sin (k x + $\omega $t) $\widehat j\,T$
Expression for corresponding electric field will be :
Where c is speed of light.

Accepted Answer

The relation between electric and magnetic field is ,
C = ${{\overrightarrow E } \over {\overrightarrow B }}$
$ \Rightarrow $$\,\,\,$ $\overrightarrow E $ = C $\overrightarrow B $
Electric field component is perpendicular to the direction of magnetic field. Given magnetic field is along y $-$ axis,
So, electric field along z $-$ axis will be
$\overrightarrow E $ = B
0
C sin (kx + $\omega $t) $\,\widehat k$ v/m

Answer

$\overrightarrow E $ = B
0
c sin (k x + $\omega $t) $\widehat k$ V/m

Answer

$\overrightarrow E $ = ${{{B_0}} \over c}$ sin  (k x + $\omega $t) $\widehat k$ V/m

Answer

$\overrightarrow E $ = $-$ B
0
c sin (kx +$\omega $t) $\widehat k$ V/m

Answer

$\overrightarrow E $ =  B
0
c sin (kx $-$$\omega $t) $\widehat k$ V/m

EM waves

Magnetic field in a plane electromagnetic wave is given by \overrightarrow B = B 0 sin (k x + \omega t) \widehat j\,T Expression for corresponding electric field will be : Where c is speed of light.

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