Question 313: Dual Nature of Matter and Radiation

Question

The threshold frequency of a metal is ' $F_0$ '. When light of frequency $2 F_0$ is incident on the metal plate, the maximum velocity of photoelectron is ' $\mathrm{V}_1$ '. When the frequency of incident radiation is increased to ' $5 \mathrm{~F}_0$ ', the maximum velocity of photoelectrons emitted is ' $V_2$ '. The ratio of $V_1$ to $V_2$ is

Accepted Answer

$$\begin{array}{ll} 
& \mathrm{KE}_{\max }=\mathrm{hF}-\mathrm{F}_0 \
& {	ext { When, } \mathrm{F}=2 \mathrm{~F}_0} \
& \frac{1}{2} \mathrm{mV}_1^2=2 \mathrm{hF}_0-\mathrm{F}_0=\mathrm{F}_0 \
& 	ext { When, } \mathrm{F}=5 \mathrm{~F}_0 \
& \frac{1}{2} \mathrm{mV} V_2^2=5 \mathrm{hF}_0-\mathrm{F}_0=4 \mathrm{~F}_0 \
	herefore \quad & \left(\frac{\mathrm{~V}_1}{\mathrm{~V}_2}ight)^2=\frac{\mathrm{F}_0}{4 \mathrm{~F}_0} \
	herefore \quad & \frac{\mathrm{~V}_1}{\mathrm{~V}_2}=\frac{1}{2}
\end{array}$$

Answer

$\frac{1}{8}$

Answer

$\frac{1}{16}$

Answer

$\frac{1}{4}$

Answer

$\frac{1}{2}$

Dual Nature of Matter and Radiation

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