Question 314: Dual Nature of Matter and Radiation

Question

For a photosensitive material, work function is ' $\mathrm{W}_0$ ' and stopping potential is ' V '. The wavelength of incident radiation is ( $\mathrm{h}=$ Planck's constant, $c=$ velocity of light, $e=$ electronic charge)

Accepted Answer

From Einstein's photoelectric equation, we can write,
$$\begin{array}{ll} 
& \mathrm{eV}=\frac{\mathrm{hc}}{\lambda}-\mathrm{W}_0 \
	herefore \quad & \frac{\mathrm{hc}}{\lambda}=\mathrm{W}_0+\mathrm{eV} \
	herefore \quad & \lambda=\frac{\mathrm{hc}}{\mathrm{~W}_0+\mathrm{eV}}
\end{array}$$

Answer

$\frac{h^2 c^2}{W_0+e V}$

Answer

$\frac{\mathrm{hc}}{\mathrm{W}_0}$

Answer

$\frac{\mathrm{hcV}}{\mathrm{W}_0}$

Answer

$\frac{\mathrm{hc}}{\mathrm{W}_0+\mathrm{eV}}$

Dual Nature of Matter and Radiation

For a photosensitive material, work function is ' \mathrm{W}_0 ' and stopping potential is ' V '. The wavelength of incident radiation is ( \mathrm{h}= Planck's constant, c= velocity of light, e= electronic charge)

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