Question 280: Dual Nature of Matter and Radiation

Question

When a light of wavelength $\lambda$ falls on the emitter of a photocell, maximum speed of emitted photoelectrons is V . If the incident wavelength is changed to $\frac{2 \lambda}{3}$, maximum speed of emitted photoelectrons will be :

Accepted Answer

$$ \begin{aligned} & \frac{\mathrm{hc}}{\lambda}=\phi_0+\frac{1}{2} \mathrm{mv}_{\max }^2 \ & \frac{3 \mathrm{hc}}{2 \lambda}=\phi_0+\frac{1}{2} \mathrm{~m}\left(\mathrm{v}_{\max }^{\prime}ight)^2 \end{aligned} $$

Answer

$\sqrt{3} \mathrm{~V}$

Answer

$\frac{\mathrm{V}}{2}$

Answer

V

Answer

$\sqrt{\frac{3}{2}} \mathrm{~V}$

Dual Nature of Matter and Radiation

When a light of wavelength \lambda falls on the emitter of a photocell, maximum speed of emitted photoelectrons is V . If the incident wavelength is changed to \frac{2 \lambda}{3}, maximum speed of emitted photoelectrons will be :

Choose the correct answer: