Question 281: Dual Nature of Matter and Radiation

Question

The de-Broglie wavelength $(\lambda)$ of a particle

Accepted Answer

The de-Broglie wavelength $\lambda$ of a particle is given by the formula:
$$ \lambda = \frac{h}{p} $$
where $h$ is Planck's constant and $p$ is the momentum (impulse) of the particle.
From the formula, $\lambda$ is
inversely proportional
to momentum (impulse).
Correct answer:
Option A: is inversely proportional to impulse.

Answer

is inversely proportional to impulse.

Answer

does not depend on impulse.

Answer

is proportional to mass.

Answer

is proportional to impulse.

Dual Nature of Matter and Radiation

The de-Broglie wavelength (\lambda) of a particle

Choose the correct answer: