Question 454: AC fundamentals

Question

An inductor of inductance 2 mH is connected to a 220 V, 50 Hz ac source. Let the inductive reactance in the circuit is X1. If a 220 V dc source replace the ac source in the circuit, then the inductive reactance in the circuit is X2. X1 and X2 respectively are :

Accepted Answer

We know, for A.C. source
$${X_L} = \omega L$$
$$ = 2\pi f(L)$$
$$ = 100\pi (2 	imes {10^{ - 3}})$$
$$ = 0.2\pi \,\Omega  = 0.628\,\Omega $$
For D.C. source
The inductor behaves as a closed circuit offering no resistance at all (at steady state) as $$\omega  = 0$$ (For D.C.)
$$	herefore$$ $${X_L} = 0\,\Omega $$

Answer

0.628 $$\Omega$$, infinity

Answer

6.28 $$\Omega$$, zero

Answer

6.28 $$\Omega$$, infinity

Answer

0.628 $$\Omega$$, zero

AC fundamentals

An inductor of inductance 2 mH is connected to a 220 V, 50 Hz ac source. Let the inductive reactance in the circuit is X1. If a 220 V dc source replace the ac source in the circuit, then the inductive reactance in the circuit is X2. X1 and X2 respectively are :

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