Question 285: Electromagnetic Induction

Question

Two coils have a mutual inductance of $$0.004 \mathrm{~H}$$. The current changes in the first coil according to equation $$\mathrm{I}=\mathrm{I}_0 \sin \omega \mathrm{t}$$, where $$\mathrm{I}_0=10 \mathrm{~A}$$ and $$\omega=50 ~\pi \mathrm{~rad} ~\mathrm{s}^{-1}$$. The maximum value of e.m.f. in the second coil in volt is

Accepted Answer

$$\begin{aligned}
& \left|e_sight|=M \frac{d I_p}{d t} \
& \left|e_sight|=M \frac{d}{d t} I_0 \sin \omega t \
\quad & \left|e_sight|=M I_0 \omega \cos \omega t \
	herefore \quad & \left|e_sight|_{\max }=M I_0 \omega=0.004 	imes 10 	imes 50 \pi \
	herefore \quad & \left|e_sight|_{\max }=(2 \pi) 	ext { volt }
\end{aligned}$$

Answer

$$5 \pi$$

Answer

$$4 \pi$$

Answer

$$2.5 \pi$$

Answer

$$2 \pi$$

Electromagnetic Induction

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