Question 286: Electromagnetic Induction

Question

The magnetic flux through a circuit of resistance '$$R$$' changes by an amount $$\Delta \phi$$ in the time $$\Delta t$$. The total quantity of electric charge '$$Q$$' which passes during this time through any point of the circuit is

Accepted Answer

According to Faraday's law of electromagnetic induction,
$$\begin{aligned}
& \varepsilon=\frac{\Delta \phi}{\Delta t} \
& \mathrm{IR}=\frac{\Delta \phi}{\Delta \mathrm{t}} \
& \mathrm{I}=\frac{\Delta \phi}{\Delta \mathrm{t} 	imes \mathrm{R}} \
& \mathrm{I} 	imes \Delta \mathrm{t}=\frac{\Delta \phi}{\mathrm{R}}
\end{aligned}$$
$$	herefore$$ The total quantity of electric charge passing through the circuit is
$$\mathrm{Q}=\frac{\Delta \phi}{\mathrm{R}}$$

Answer

$$-\frac{\Delta \phi}{\Delta t}+R$$

Answer

$$\frac{\Delta \phi}{\mathrm{R}}$$

Answer

$$\frac{\Delta \phi}{\Delta t}$$

Answer

$$\frac{\Delta \phi}{\Delta t} 	imes R$$

Electromagnetic Induction

The magnetic flux through a circuit of resistance '$R' changes by an amount \Delta \phi in the time \Delta t. The total quantity of electric charge 'Q$' which passes during this time through any point of the circuit is

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