Question 186: Waves

Question

Equation of travelling wave on a stretched string of linear density 5 g/m is y = 0.03 sin(450 t – 9x) where distance and time are measured in SI units. The tension in the string is :

Accepted Answer

y = 0.03 sin(450 t $$-$$ 9x)
v = $${\omega  \over k} = {{450} \over 9}$$ = 50m/s
v = $$\sqrt {{T \over \mu }}  \Rightarrow {T \over \mu }$$ = 2500
$$ \Rightarrow $$  T = 2500 $$ 	imes $$ 5 $$ 	imes $$ 10
$$-$$3
= 12.5 N

Answer

10 N

Answer

7.5 N

Answer

5 N

Answer

12.5 N

Waves

Equation of travelling wave on a stretched string of linear density 5 g/m is y = 0.03 sin(450 t – 9x) where distance and time are measured in SI units. The tension in the string is :

Choose the correct answer: