Question 187: Waves

Question

A string of length 1 m and mass 5 g is fixed at both ends. The tension in the string is 8.0 N. The string is set into vibration using an external vibrator of frequency 100 Hz. The separation between successive nodes on the string is close to -

Accepted Answer

Velocity of wave on string
$$V = \sqrt {{T \over \mu }}  = \sqrt {{8 \over 5} 	imes 1000}  = 40m/s$$
Now, wavelength of wave
$$\lambda  = {v \over n} = {{40} \over {100}}m$$
Separation b/w successive nodes,
$${\lambda  \over 2} = {{20} \over {100}}\,m$$ $$=$$ 20 cm

Answer

16.6 cm

Answer

10.0 cm

Answer

20.0 cm

Answer

33.3 cm

Waves

A string of length 1 m and mass 5 g is fixed at both ends. The tension in the string is 8.0 N. The string is set into vibration using an external vibrator of frequency 100 Hz. The separation between successive nodes on the string is close to -

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