Question 917: Thermodynamics & KTG

Question

The change in internal energy of the mass of a gas, when the volume changes from '$$\mathrm{V}$$' to '$$2 \mathrm{~V}$$' at constant pressure 'P' is ($$\gamma=$$ Ratio of Cp to Cv)

Accepted Answer

$$\begin{aligned}
& \Delta \mathrm{U}=\mathrm{nC}_{\mathrm{v}} \Delta \mathrm{T} \
& =\mathrm{n} \frac{\mathrm{R}}{\gamma-1} \Delta \mathrm{T} \
& =\frac{\mathrm{P} \Delta \mathrm{V}}{\gamma-1}=\frac{\mathrm{PV}}{\gamma-1} \
& \because \Delta \mathrm{V}=2 \mathrm{V}-\mathrm{V} \
&
\end{aligned}$$

Answer

$$\frac{\mathrm{PV}}{(\gamma-1)}$$

Answer

$$\frac{\mathrm{P}}{(\gamma-1)}$$

Answer

PV

Answer

$$\frac{\gamma \mathrm{PV}}{(\gamma-1)}$$

Thermodynamics & KTG

The change in internal energy of the mass of a gas, when the volume changes from '$\mathrm{V}' to '2 \mathrm{~V}' at constant pressure 'P' is (\gamma=$ Ratio of Cp to Cv)

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