Question 918: Thermodynamics & KTG

Question

If the pressure of an ideal gas is decreased by $$10 \%$$ isothermally, then its volume will

Accepted Answer

For isothermal process, $$\mathrm{P}_1 \mathrm{V}_1=\mathrm{P}_2 \mathrm{V}_2$$
$$\mathrm{P}_2=\mathrm{P}_1-\frac{\mathrm{P}_1}{10}=\frac{9}{10} \mathrm{P}_1$$
$$\begin{aligned}
	herefore \mathrm{P}_1 \mathrm{V}_1 & =\frac{9}{10} \mathrm{P}_1 \mathrm{V}_2 \
	herefore \mathrm{V}_2 & =\frac{10}{9} \mathrm{V}_1 \
& =1.11 \mathrm{V}_1 \
& =\mathrm{V}_1+0.11 \mathrm{V}_1
\end{aligned}$$

Answer

decrease by $$8 \%$$

Answer

decrease by $$9 \%$$

Answer

increase by $$8 \%$$

Answer

increase by $$11.1 \%$$

Thermodynamics & KTG

If the pressure of an ideal gas is decreased by $10 \%$ isothermally, then its volume will

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