Question 139: Motion in 1D

Question

The displacement 'x' (in meter) of a particle of mass 'm' (in kg) moving in one dimension under the action of a force, is related to time 't' (in sec) by t = $$\sqrt x  + 3$$. The displacement of the particle when its velocity is zero,  will be

Accepted Answer

As t = $$\sqrt x  + 3$$
$$ \Rightarrow $$ $$\sqrt x  = t - 3$$
$$ \Rightarrow $$ $$x = {\left( {t - 3} \right)^2}$$
Velocity, v = $${{dx} \over {dt}}$$ = 2($$t - 3$$)
Velocity of the particle becomes zero, when
2($$t - 3$$) = 0 $$ \Rightarrow $$ t = 3 s
At t = 3 s,
$$x = {\left( {3 - 3} \right)^2}$$ = 0 m

Answer

4 m

Answer

0 m (zero)

Answer

6 m

Answer

2 m

Motion in 1D

The displacement 'x' (in meter) of a particle of mass 'm' (in kg) moving in one dimension under the action of a force, is related to time 't' (in sec) by t = $\sqrt x + 3$. The displacement of the particle when its velocity is zero, will be

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