Question 140: Motion in 1D

Question

A stone falls freely under gravity. It covers distances h1, h2 and h3 in the first 5 seconds,  the next 5 seconds and the next 5 seconds respectively. The relation between h1, h2 and h3 is

Accepted Answer

Here h = $${1 \over 2}g{t^2}$$
$$ 	herefore $$ h
1
= $${1 \over 2}g{\left( 5 ight)^2}$$ = 125
h
1
+ h
2
= $${1 \over 2}g{\left( 10 ight)^2}$$ = 500
$$ \Rightarrow $$ h
2
= 375
h
1
+ h
2
+ h
3
= $${1 \over 2}g{\left( 15 ight)^2}$$ = 1125
$$ \Rightarrow $$ h
3
= 625
$$ 	herefore $$ h
2
= 3h
1
and h
3
= 5h
1
or $${h_1}$$ = $${{{h_2}} \over 3}$$ = $${{{h_3}} \over 5}$$

Answer

h2 = 3h1  and  h3 = 3h2

Answer

h1 = h2 = h3

Answer

h1 = 2h2 = 3h3

Answer

$${h_1}$$ = $${{{h_2}} \over 3}$$ = $${{{h_3}} \over 5}$$

Motion in 1D

A stone falls freely under gravity. It covers distances h1, h2 and h3 in the first 5 seconds, the next 5 seconds and the next 5 seconds respectively. The relation between h1, h2 and h3 is

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