Question 198: Laws of Motion

Question

The mass of the lift is 200 kg , when it ascends with an acceleration of $4 \mathrm{~m} / \mathrm{s}^2$ then the tension in the cable supporting the lift will be [Given: Acceleration due to gravity $g=10 \mathrm{~m} / \mathrm{s}^2$ ]

Accepted Answer

$$\begin{aligned}
&	ext { The equation of motion for the lift is: }\
&\begin{aligned}
T & -m a=m g \
T & =m(g+a) \
& =200(10+4) \
T & =2800 \mathrm{~N}
\end{aligned}
\end{aligned}$$

Answer

800 N

Answer

2800 N

Answer

4200 N

Answer

2000 N

Laws of Motion

The mass of the lift is 200 kg , when it ascends with an acceleration of 4 \mathrm{~m} / \mathrm{s}^2 then the tension in the cable supporting the lift will be [Given: Acceleration due to gravity g=10 \mathrm{~m} / \mathrm{s}^2 ]

Choose the correct answer: