Question 10: Laws of Motion

Question

Four blocks of same mass connected by strings are pulled by a force $$F$$ on a smooth horizontal surface as shown in figure. The tension $$T_1, T_2$$ and $$T_3$$ will be

Accepted Answer

Given situation can be represented as,
$$\begin{aligned}
F & \leftarrow m_1 ightarrow T_1 \leftarrow m_2 ightarrow T_2 \leftarrow m_3 ightarrow T_3 \leftarrow m_4 \
T_1 & =\frac{\left(m_2+m_3+m_4ight)}{m_1+m_2+m_3+m_4} F
\end{aligned}$$
Given, $$m_1=m_2=m_3=m_4=m$$
$$\begin{array}{ll}
	herefore & T_1=\frac{3}{4} F \
	ext { Similarly, }, & T_2=\frac{\left(m_3+m_4ight) F}{m_1+m_2+m_3+m_4} \
	herefore & T_2=\frac{1}{2} F \
	ext { Also, } & T_3=\frac{m_4 F}{m_1+m_2+m_3+m_4} \
\Rightarrow \quad & T_3=\frac{1}{4} F
\end{array}$$

Answer

$$T_1=\frac{1}{4} F, T_2=\frac{3}{2} F, T_3=\frac{1}{4} F$$

Answer

$$T_1=\frac{1}{4} F, T_2=\frac{1}{2} F, T_3=\frac{1}{2} F$$

Answer

$$T_1=\frac{3}{4} F, T_2=\frac{1}{2} F, T_3=\frac{1}{4} F$$

Answer

$$T_1=\frac{3}{4} F, T_2=\frac{1}{2} F, T_3=\frac{1}{2} F$$

Laws of Motion

Four blocks of same mass connected by strings are pulled by a force $F on a smooth horizontal surface as shown in figure. The tension T_1, T_2 and T_3$ will be

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