Question 210: Laws of Motion

Question

A box of mass $$5 \mathrm{~kg}$$ is pulled by a cord, up along a frictionless plane inclined at $$30^{\circ}$$ with the horizontal. The tension in the cord is $$30 \mathrm{~N}$$. The acceleration of the box is (Take $$g=10 \mathrm{~m} \mathrm{~s}^{-2}$$)

Accepted Answer

$$T-M g \sin 30=M a$$
$$\begin{aligned}
& 30-5 	imes 10 	imes \frac{1}{2}=5 a \
& a=1 \mathrm{~m} / \mathrm{s}^2
\end{aligned}$$

Answer

$$2 \mathrm{~m} \mathrm{~s}^{-2}$$

Answer

Zero

Answer

$$0.1 \mathrm{~m} \mathrm{~s}^{-2}$$

Answer

$$1 \mathrm{~m} \mathrm{~s}^{-2}$$

Laws of Motion

A box of mass $5 \mathrm{~kg} is pulled by a cord, up along a frictionless plane inclined at 30^{\circ} with the horizontal. The tension in the cord is 30 \mathrm{~N}. The acceleration of the box is (Take g=10 \mathrm{~m} \mathrm{~s}^{-2}$)

Choose the correct answer: