Question 92: Laws of Motion

Question

A block of mass M slides down on a rough inclined plane with constant velocity. The angle made by the incline plane with horizontal is $$	heta$$. The magnitude of the contact force will be :

Accepted Answer

As the body is moving with constant velocity so forces acting on the body must be balanced.
$$\Rightarrow$$ Contact force from incline should balance weight of the body.
$$\Rightarrow$$ | F
contact
| = Mg

Answer

Mg

Answer

$$\mathrm{Mg} \cos 	heta$$

Answer

$$\sqrt{\mathrm{Mg} \sin 	heta+\mathrm{Mg} \cos 	heta}$$

Answer

$$\operatorname{Mg} \sin 	heta \sqrt{1+\mu}$$

Laws of Motion

A block of mass M slides down on a rough inclined plane with constant velocity. The angle made by the incline plane with horizontal is $\theta$. The magnitude of the contact force will be :

Choose the correct answer: