Question 257: Work, Energy and Power & Circular Motion

Question

A force $$\mathrm{F}=\left(5+3 y^{2}\right)$$ acts on a particle in the $$y$$-direction, where $$\mathrm{F}$$ is in newton and $$y$$ is in meter. The work done by the force during a displacement from $$y=2 \mathrm{~m}$$ to $$y=5 \mathrm{~m}$$ is ___________ J.

Accepted Answer

$\begin{aligned} & W=\int F d y=\int_2^5\left(5+3 y^2ight) d y \\ & =\left.\left(5 y+y^3ight)ight|_2 ^5 \\ & =(15+125-8) \mathrm{J} \\ & =132 \mathrm{~J}\end{aligned}$

Work, Energy and Power & Circular Motion

A force $\mathrm{F}=\left(5+3 y^{2}\right) acts on a particle in the y-direction, where \mathrm{F} is in newton and y is in meter. The work done by the force during a displacement from y=2 \mathrm{~m} to y=5 \mathrm{~m}$ is ___________ J.

Integer / Numeric Answer Type