Question 69: Work, Energy and Power & Circular Motion

Question

A particle is placed at the point $$A$$ of a frictionless track $$A B C$$ as shown in figure. It is gently pushed towards right. The speed of the particle when it reaches the point B is :
(Take $$g=10 \mathrm{~m} / \mathrm{s}^2$$).

Accepted Answer

By COME
$$\begin{aligned}
& \mathrm{KE}_{\mathrm{A}}+\mathrm{U}_{\mathrm{A}}=\mathrm{KE}_{\mathrm{B}}+\mathrm{U}_{\mathrm{B}} \
& 0+\mathrm{mg}(1)=\frac{1}{2} \mathrm{mv}^2+\mathrm{mg} 	imes 0.5 \
& v=\sqrt{g}=\sqrt{10} \mathrm{~m} / \mathrm{s}
\end{aligned}$$

Answer

$$2 \sqrt{10} \mathrm{~m} / \mathrm{s}$$

Answer

$$10 \mathrm{~m} / \mathrm{s}$$

Answer

$$\sqrt{10} \mathrm{~m} / \mathrm{s}$$

Answer

$$20 \mathrm{~m} / \mathrm{s}$$

Work, Energy and Power & Circular Motion

A particle is placed at the point $A of a frictionless track A B C as shown in figure. It is gently pushed towards right. The speed of the particle when it reaches the point B is : (Take g=10 \mathrm{~m} / \mathrm{s}^2$).

Choose the correct answer: