Question 260: Work, Energy and Power & Circular Motion

Question

Two particles having mass '$M$' and '$m$' are moving in a circular path with radius '$R$' and '$r$' respectively. The time period for both the particles is same. The ratio of angular velocity of the first particle to the second particle will be

Accepted Answer

$\begin{aligned}
& \mathrm{T}=\frac{2 \pi}{\omega} \
& 	ext { Hence, } \mathrm{T}_1=\mathrm{T}_2 \
& \Rightarrow \omega_1=\omega_2 \
& 	herefore \quad \frac{\omega_1}{\omega_2}=\frac{1}{1}
\end{aligned}$

Answer

1 : 1

Answer

1 : 2

Answer

2 : 3

Answer

3 : 4

Work, Energy and Power & Circular Motion

Two particles having mass 'M' and 'm' are moving in a circular path with radius 'R' and 'r' respectively. The time period for both the particles is same. The ratio of angular velocity of the first particle to the second particle will be

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