Question 220: Work, Energy and Power & Circular Motion

Question

A spring of force constant $800$ $N/m$ has an extension of $5$ $cm.$ The work done in extending it from $5$ $cm$ to $15$ $cm$ is

Accepted Answer

When we extend the spring by $dx$ then the work done
$dW = k\,x\,dx$
Applying integration both sides we get,
$	herefore$ $W = k\int\limits_{0.05}^{0.15} {x\,dx} $
$ = {{800} \over 2}\left[ {{{\left( {0.15} ight)}^2} - {{\left( {0.05} ight)}^2}} ight] $
$= 8\,J$

Answer

$16J$

Answer

$8J$

Answer

$32J$

Answer

$24J$

Work, Energy and Power & Circular Motion

A spring of force constant 800 N/m has an extension of 5 cm. The work done in extending it from 5 cm to 15 cm is

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