Question 105: Work, Energy and Power & Circular Motion

Question

In the given figure, the block of mass m is dropped from the point 'A'. The expression for kinetic energy of block when it reaches point 'B' is

Accepted Answer

Loss in potential energy = gain in kinetic energy
$$-$$ (mg(y $$-$$ y
0
) $$-$$ mgy) = KE $$-$$ 0
$$\Rightarrow$$ KE = mgy
0

Answer

$${1 \over 2}mg\,{y_0}^2$$

Answer

$${1 \over 2}mg\,{y^2}$$

Answer

$$mg(y - {y_0})$$

Answer

$$mg{y_0}$$

Work, Energy and Power & Circular Motion