Question 360: Waves

Question

If the end correction of an open pipe is $$0.8 \mathrm{~cm}$$, then the inner radius of that pipe is

Accepted Answer

For an open pipe, $$\mathrm{e}=0.6 \mathrm{~d}$$
$$\begin{array}{ll}
	herefore & \mathrm{d}=\frac{\mathrm{e}}{0.6} \
	herefore & 2 \mathrm{r}=\frac{\mathrm{e}}{0.6} \
	herefore & \mathrm{r}=\frac{0.8}{1.2}=\frac{2}{3} \mathrm{~cm}
\end{array}$$

Answer

$$\frac{1}{3} \mathrm{~cm}$$

Answer

$$\frac{2}{3} \mathrm{~cm}$$

Answer

$$\frac{3}{2} \mathrm{~cm}$$

Answer

$$0.2 \mathrm{~cm}$$

Waves

If the end correction of an open pipe is $0.8 \mathrm{~cm}$, then the inner radius of that pipe is

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