Question 314: Wave Optics

Question

When two light waves each of amplitude '$$A$$' and having a phase difference of $$\frac{\pi}{2}$$ superimposed then the amplitude of resultant wave is

Accepted Answer

The formula for resultant amplitude is,
$$R=\sqrt{A_1^2+A_2^2+2 A_1 A_2 \cos \phi}$$
Here, $$A_1=A_2=A$$ and $$\phi=90^{\circ}$$
$$	herefore \quad R=\sqrt{A^2+A^2+2 A^2 \cos 90^{\circ}}=\sqrt{2 A^2}=\sqrt{2} A$$

Answer

$$\frac{\mathrm{A}}{\sqrt{2}}$$

Answer

$$2 \mathrm{~A}$$

Answer

$$\sqrt{2} \mathrm{~A}$$

Answer

$$\frac{\mathrm{A}}{2}$$

Wave Optics

When two light waves each of amplitude '$A' and having a phase difference of \frac{\pi}{2}$ superimposed then the amplitude of resultant wave is

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