Question 11: Wave Optics

Question

The Young's double slit experiment is performed with blue and green light of wavelengths 4360 Å and 5460 Å respectively. If $$x$$ is the distance of 4th maxima from the central one, then

Accepted Answer

In YoungÃ¢ÂÂs double slit experiment position
of bright fringes on the screen are given by
$$x=\frac{n D \lambda}{d}$$
Hence, distance of $$n$$th maxima will be
$$\begin{aligned}
x & =n \lambda \frac{D}{d} \propto \lambda \
\lambda_{	ext {blue }} & =4360 \mathop A\limits^o \
\lambda_{	ext {green }} & =5480 \mathop A\limits^o
\end{aligned}$$
$$x=$$ distance of 4th maxima from the central are
$$\begin{array}{ll}
	ext { As } & \lambda_{	ext {blue }}< \lambda_{	ext {green }} \
	herefore & x_{	ext {blue }}< x_{	ext {green }}
\end{array}$$

Answer

$$x_{	ext {blue }}=x_{	ext {green }}$$

Answer

$$x_{	ext {blue }}> x_{	ext {green }}$$

Answer

$$x_{	ext {blue }}< x_{	ext {green }}$$

Answer

$$x_{	ext {blue }} / x_{	ext {green }}$$

Wave Optics

The Young's double slit experiment is performed with blue and green light of wavelengths 4360 Å and 5460 Å respectively. If $x$ is the distance of 4th maxima from the central one, then

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