Question 191: Wave Optics

Question

Two slits are $$1 \mathrm{~mm}$$ apart and the screen is located $$1 \mathrm{~m}$$ away from the slits. A light of wavelength $$500 \mathrm{~nm}$$ is used. The width of each slit to obtain 10 maxima of the double slit pattern within the central maximum of the single slit pattern is __________ $$	imes 10^{-4} \mathrm{~m}$$.

Accepted Answer

$$\begin{aligned}
& 	ext { Width central maxima }=10 	ext { fringe width }=\frac{2 \lambda 	heta}{a}=10 \beta \
& \frac{2 \lambda 	heta}{a}=10 	imes \frac{\lambda D}{d} \
& a=\frac{d}{5}=\frac{10^{-3}}{5}=2 	imes 10^{-4}
\end{aligned}$$

Wave Optics

Integer / Numeric Answer Type