Question 239: Wave Optics

Question

In a single slit diffraction experiment, slit of width ' $a$ ' is illuminated by light of wavelength ' $\lambda$ ' and the width of the central maxima in diffraction pattern is measured as ' $y$ '. When half of the slit is covered and illuminated by light of wavelength (1.5) $\lambda$, the width of the central maximum in diffraction pattern becomes

Accepted Answer

$$ \begin{aligned} &y=\frac{2 \lambda D}{d}\ &	ext { When half the slit is covered, } d^{\prime}=\frac{d}{2}, \lambda^{\prime}=1.5 \lambda\ 	herefore \,\, &W^{\prime}=\frac{2 \lambda^{\prime} D}{\frac{d}{2}} \end{aligned} $$
$$ \begin{array}{ll} 	herefore & \frac{y^{\prime}}{y}=\frac{2 \lambda^{\prime}}{\lambda}=\frac{2 	imes 1.5 \lambda}{\lambda} \ 	herefore & \frac{y^{\prime}}{y}=3 \ 	herefore & y^{\prime}=3 y \end{array} $$

Answer

$\frac{3}{2} y$

Answer

$\frac{2}{3} y$

Answer

$3 y$

Answer

$\frac{\mathrm{y}}{3}$

Wave Optics

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