Question 84: Wave Optics

Question

The width of one of the two slits in a Young's double slit experiment is 4 times that of the other slit. The ratio of the maximum of the minimum intensity in the interference pattern is:

Accepted Answer

$$\begin{aligned}
& I_{\max }=\left(\sqrt{4 I_0}+\sqrt{I_0}ight)^2=\left(3 \sqrt{I_0}ight)^2=9 I_0 \
& I_{\min }=\left(\sqrt{4 I_0}-\sqrt{I_0}ight)^2=I_0 \
& \frac{I_{\max }}{I_{\min }}=9: 1
\end{aligned}$$

Answer

$$1: 1$$

Answer

$$4: 1$$

Answer

$$16: 1$$

Answer

$$9: 1$$

Wave Optics

The width of one of the two slits in a Young's double slit experiment is 4 times that of the other slit. The ratio of the maximum of the minimum intensity in the interference pattern is:

Choose the correct answer: