Question 195: Wave Optics

Question

In Young's double slit experiment, carried out with light of wavelength $$5000~\mathop A\limits^o$$, the distance between the slits is $$0.3 \mathrm{~mm}$$ and the screen is at $$200 \mathrm{~cm}$$ from the slits. The central maximum is at $$x=0 \mathrm{~cm}$$. The value of $$x$$ for third maxima is __________ $$\mathrm{mm}$$.

Accepted Answer

$$\begin{aligned}
x & =\frac{3 \lambda D}{d} \
& =\frac{3 	imes 5000 	imes 10^{-10} 	imes 200 	imes 10^{-2}}{0.3 	imes 10^{-3}} \
& =10 \mathrm{~mm}
\end{aligned}$$

Wave Optics

Integer / Numeric Answer Type