Question 430: Wave Optics

Question

The Brewster's law is given by the expression

Accepted Answer

The correct option for Brewster's Law is:
Option B
$$\mu=	an 	heta_p$$
Brewster's law relates the refractive index of a material to the angle of polarization, denoted as $	heta_p$, at which light with a particular polarization is perfectly transmitted through a transparent dielectric surface, with no reflection. When light hits the surface at this angle, the reflected light is perfectly polarized perpendicular to the plane of incidence. Mathematically, Brewster's law is given by:
$$\mu = 	an 	heta_p$$
where $\mu$ is the refractive index of the material and $	heta_p$ is the Brewster's angle. According to this law, $\mu$ is the tangent of the Brewster's angle ($	heta_p$), which is the angle of incidence at which light with its electric vector perpendicular to the incidence plane (p-polarized) is not reflected.
The other options given are representations of different laws or relationships in physics, not Brewster's law. For instance, Option A represents Snell's law of refraction, expressed incorrectly here as the correct form would be $\mu = \frac{\sin i}{\sin r}$, where $\mu$ is the refractive index, $i$ is the angle of incidence, and $r$ is the angle of refraction. Options C and D do not represent the correct expression for Brewster's law or any directly related optical principle in this context.

Answer

$$\mu=\frac{\sin i}{\sin r}$$

Answer

$$\mu=	an 	heta p$$

Answer

$$\mu=\cos 	heta$$

Answer

$$\mu=\sin 	heta$$

Wave Optics

The Brewster's law is given by the expression

Choose the correct answer: