Question 125: Wave Optics

Question

Two light waves having the same wavelength $$\lambda $$ in vacuum are in phase initially. Then the first wave
travels a path L
1
through a medium of refractive index n
1
while the second wave travels a path of length
L
2
through a medium of refractive index n
2
. After this the phase difference between the two waves is :

Accepted Answer

Phase difference = $${{2\pi } \over \lambda }$$ $$ 	imes $$ optical path difference
= $${{2\pi } \over \lambda }\left( {{n_1}{L_1} - {n_2}{L_2}} ight)$$

Answer

$${{2\pi } \over \lambda }\left( {{n_1}{L_1} - {n_2}{L_2}} \right)$$

Answer

$${{2\pi } \over \lambda }\left( {{n_2}{L_1} - {n_1}{L_2}} \right)$$

Answer

$${{2\pi } \over \lambda }\left( {{{{L_1}} \over {{n_1}}} - {{{L_2}} \over {{n_2}}}} \right)$$

Answer

$${{2\pi } \over \lambda }\left( {{{{L_2}} \over {{n_1}}} - {{{L_1}} \over {{n_2}}}} \right)$$

Wave Optics

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