Question 132: Wave Optics

Question

Visible light of wavelength 6000 $$ 	imes $$ 10
-8
cm falls normally on a single slit and produces a diffraction pattern. It is found that the second diffraction minimum is at 60
o
from the central maximum. If the first minimum is produced at $$	heta $$
1
, then $$	heta $$
1
, is close to :

Accepted Answer

For 2
nd
minima
$$\sin 	heta  = {{2\lambda } \over d }$$
$$ \Rightarrow $$ $$\sin 60^\circ  = {{2\lambda } \over d}$$
$$ \Rightarrow $$ $${\lambda  \over d} = {{\sqrt 3 } \over 4}$$
For 1
st
minima
$$\sin {	heta _1} = {\lambda  \over d}$$ = $${{\sqrt 3 } \over 4}$$
$$ \Rightarrow $$ $${	heta _1} = $$ 25
o

Answer

45
o

Answer

30
o

Answer

25
o

Answer

20
o

Wave Optics

Visible light of wavelength 6000 $ \times 10 -8 cm falls normally on a single slit and produces a diffraction pattern. It is found that the second diffraction minimum is at 60 o from the central maximum. If the first minimum is produced at \theta 1 , then \theta $ 1 , is close to :

Choose the correct answer: