Question 333: Wave Optics

Question

A double slit experiment is immersed in water of refractive index 1.33. The slit separation is $$1 \mathrm{~mm}$$, distance between slit and screen is $$1.33 \mathrm{~m}$$ The slits are illuminated by a light of wavelength $$6300 \mathop A\limits^o$$. The fringe width is

Accepted Answer

$$\begin{aligned}
& \lambda_{	ext {liquid }}=\frac{\lambda_{	ext {air }}}{\mu} \
& \lambda_{	ext {liquid }}=\frac{6300 	imes 10^{-10}}{1.33}
\end{aligned}$$
Fringe width,
$$\mathrm{W}=\frac{\lambda_{	ext {liquid }} 	imes \mathrm{D}}{\mathrm{d}}=\frac{6300 	imes 10^{-10} 	imes 1.33}{1.33 	imes 0.001}=6.3 	imes 10^{-4} \mathrm{~m}$$

Answer

$$4.9 	imes 10^{-4} \mathrm{~m}$$

Answer

$$5.8 	imes 10^{-4} \mathrm{~m}$$

Answer

$$6.3 	imes 10^{-4} \mathrm{~m}$$

Answer

$$8.6 	imes 10^{-4} \mathrm{~m}$$

Wave Optics

A double slit experiment is immersed in water of refractive index 1.33. The slit separation is $1 \mathrm{~mm}, distance between slit and screen is 1.33 \mathrm{~m} The slits are illuminated by a light of wavelength 6300 \mathop A\limits^o$. The fringe width is

Choose the correct answer: