Question 223: Wave Optics

Question

A fringe width of 6 mm was produced for two slits separated by 1 mm apart. The screen is placed 10 m away. The wavelength of light used is 'x' nm. The value of 'x' to the nearest integer is ____________.

Accepted Answer

$$\beta$$ = 6 mm, d = 1 mm, D = 10 m
$$\lambda$$ = ?
We know, $$\beta  = {{\lambda D} \over d}$$
6 $$	imes$$ 10
$$-$$3
= $${{\lambda  	imes 10} \over {1 	imes {{10}^{ - 3}}}}$$
$$ 	herefore $$ $$\lambda$$ = $${{6 	imes {{10}^{ - 3}} 	imes 1 	imes {{10}^{ - 3}}} \over {10}}$$
$$\lambda$$ = 600 $$	imes$$ 10
$$-$$9
m
$$ 	herefore $$ $$\lambda$$ = 600 nm

Wave Optics

A fringe width of 6 mm was produced for two slits separated by 1 mm apart. The screen is placed 10 m away. The wavelength of light used is 'x' nm. The value of 'x' to the nearest integer is ____________.

Integer / Numeric Answer Type