Question 261: Units , Dimensions and Error Analysis

Question

Figure 1 shows the configuration of main scale and Vernier scale before measurement. Fig. 2 shows the configuration corresponding to the measurement of diameter
D
of a tube. The measured value of
D
is:
![](https://app-content.cdn.examgoal.net/fly/@width/image/jaoe38c1mb0d9wo5/ff2003e3-bb0a-41bd-ac30-ea4aed1b4788/b2f70d50-3797-11f0-831e-111c9abd7f64/file-jaoe38c1mb0d9wo6.png?format=png)

Accepted Answer

For vernier scale,
$ \begin{aligned} & 10 \mathrm{div}=7 \mathrm{~mm} \ & 1 \mathrm{div}=0.7 \mathrm{~mm} \end{aligned} $
Reading: main scale $=1 \mathrm{~mm}$
VS 1 marking matches with MS div
So VS reads $(1-0.7 \mathrm{~mm})=0.3 \mathrm{~mm}$
$ \begin{aligned} 	ext { So total } & =(1+0.3) \mathrm{mm} \ & =1.3 \mathrm{~mm} \ & =0.13 \mathrm{~cm} 	ext { Ans. } \end{aligned} $

Answer

0.12 cm

Answer

0.11 cm

Answer

0.13 cm

Answer

0.14 cm

Units , Dimensions and Error Analysis

Figure 1 shows the configuration of main scale and Vernier scale before measurement. Fig. 2 shows the configuration corresponding to the measurement of diameter D of a tube. The measured value of D is:

Choose the correct answer: