Question 1: Thermodynamics & KTG

Question

An ideal gas is undergoing a cyclic thermodynamic process in different ways as shown in the corresponding $P-V$ diagram in column 3 of the table. Consider only the path from state $1$ to state $2.$ $W$ denotes the corresponding work done on the system. The equations and plots in the table have standard notations as used in thermodynamic processes. Here $Y$ is the ratio of heat capacities at constant pressure and constant volume. The number of moles in the gas is $n.$
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Accepted Answer

Compare the given relation, $\Delta$U = $\Delta$Q $-$ p$\Delta$V, with the first law of thermodynamics, $\Delta$Q = $\Delta$U + $\Delta$W, to get work done by the gas as $\Delta$W = p$\Delta$V. This is the work done in an isobaric process. The p-V diagram of this process is shown in (P). The work done in this process is ${W_{1 	o 2}} = \int {pdV = p{V_1} - p{V_2}} $.

Answer

$\left( {{\rm I}{\rm I}} \right)\left( {iv} \right)\left( R \right)$

Answer

$\left( {{\rm I}{\rm I}{\rm I}} \right)\left( {iii} \right)\left( P \right)$

Answer

$\left( {{\rm I}{\rm I}} \right)\left( {iii} \right)\left( S \right)$

Answer

$\left( {{\rm I}{\rm I}} \right)\left( {iii} \right)\left( P \right)$

Thermodynamics & KTG

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