Question 488: Thermodynamics & KTG

Question

Time taken by a $$836$$ $$W$$ heater to heat one litre of water from $$10{}^ \circ C$$ to $$40{}^ \circ C$$ is

Accepted Answer

$$\Delta Q = mC 	imes \Delta T$$
$$ = 1 	imes 4180 	imes \left( {40 - 10} ight) = 80 	imes 30$$
( $$	herefore$$ $$\Delta Q = $$ heat supplied in time $$t$$ for heating $$1L$$ water from $${10^ \circ }C$$ to $${40^ \circ }C$$ )
also $$\Delta Q = 836 	imes t \Rightarrow t = {{4180 	imes 30} \over {836}} = 150\,s$$

Answer

$$150$$ $$s$$

Answer

$$100$$ $$s$$

Answer

$$50$$ $$s$$

Answer

$$200$$ $$s$$

Thermodynamics & KTG

Time taken by a $836 W heater to heat one litre of water from 10{}^ \circ C to 40{}^ \circ C$ is

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