Question 280: Thermodynamics & KTG

Question

For a perfect gas, two pressures P
1
and P
2
are shown in figure. The graph shows :
![](https://app-content.cdn.examgoal.net/fly/@width/image/1l58mc56o/fedd339f-e77e-491e-86ee-0a344b5d9866/529adb10-fca0-11ec-af50-7b1dc1e93a30/file-1l58mc56p.png?format=png)

Accepted Answer

As per ideal gas equation, $V = {{nR} \over P}T$
$\Rightarrow$ Slope of V-T graph is inversely proportional to P.
As m
2
> m
1
$\Rightarrow$ P
1
> P
2

Answer

P
1
> P
2

Answer

P
1
< P
2

Answer

P
1
= P
2

Answer

Insufficient data to draw any conclusion

Thermodynamics & KTG

For a perfect gas, two pressures P 1 and P 2 are shown in figure. The graph shows :

Choose the correct answer: