Question 1: Thermodynamics & KTG

Question

$C_V$ and $C_P$ denote the molar specific heat capacities of a gas at constant volume and constant pressure, respectively. Then

Accepted Answer

We know that ${C_P} - {C_V} = R$ is same for all gases. For a diatomic gas, we have
${C_V} = {{5R} \over 2}$
Therefore, ${C_P} = {C_V} + R = {{7R} \over 2}$
For a monoatomic gas, we have
${C_V} = {{3R} \over 2}$
${C_P} = {{5R} \over 2}$
Therefore,
${C_P} + {C_V} = 6R$ (diatomic)
${C_P} + {C_V} = 4R$ (monoatomic)
${{{C_P}} \over {{C_V}}} = {7 \over 5} = 1.4$ (diatomic)
${{{C_P}} \over {{C_V}}} = {5 \over 3} = 1.67$ (monoatomic)
${C_P}\,.\,{C_V} = {{35{R^2}} \over 4}$ (diatomic)
${C_P}\,.\,{C_V} = {{15{R^2}} \over 4}$ (monoatomic)

Answer

$C_P-C_V$ is larger for a diatomic ideal gas than for a monoatomic ideal gas.

Answer

$C_P+C_V$ is larger for a diatomic ideal gas than for a monoatomic ideal gas.

Answer

$C_P/C_V$ is larger for a diatomic ideal gas than for a monoatomic ideal gas.

Answer

$C_P~.C_V$ is larger for a diatomic ideal gas than for a monoatomic ideal gas.

Thermodynamics & KTG

C_V and C_P denote the molar specific heat capacities of a gas at constant volume and constant pressure, respectively. Then

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