Question 531: Thermodynamics & KTG

Question

A block of ice of mass 120 g at temperature 0$$^\circ$$C is put in 300 g of water at 25$$^\circ$$C. The x g of ice melts as the temperature of the water reaches 0$$^\circ$$C. The value of x is _____________.
[Use specific heat capacity of water = 4200 Jkg
$$-$$1
K
$$-$$1
, Latent heat of ice = 3.5 $$	imes$$ 10
5
Jkg
$$-$$1
]

Accepted Answer

Heat lost by water = Heat gained by ice
$$0.3 	imes 4200 	imes 25 = x 	imes 3.5 	imes {10^5}$$
$$x = {{0.3 	imes 4200 	imes 25} \over {3.5 	imes {{10}^5}}}$$
$$ = 90 	imes 100 	imes {10^5} 	imes {10^3}$$ gram = 90 gm

Thermodynamics & KTG

Integer / Numeric Answer Type