Question 966: Thermodynamics & KTG

Question

An ideal gas goes from state A to state B via three different processes as indicated in the P-V diagram.
If Q
1
, Q
2
, Q
3
indicate the heat absorbed by the gas along the three processes and $$\Delta $$U
1
, $$\Delta $$U
2
,  $$\Delta $$U
3
indicate the change in internal energy along the three processes respectively, then

Accepted Answer

Initial and final condition is same for all process
$$\Delta {U_1} = \Delta {U_2} = \Delta {U_3}$$
from first law of thermodynamics
$$\Delta Q = \Delta U + \Delta W$$
Work done
$$\Delta {W_1} > \Delta {W_2} > \Delta {W_3}$$   (Area of P.V. graph)
So $$\Delta {Q_1} > \Delta {Q_2} > \Delta {Q_3}$$

Answer

Q
1
> Q
2
> Q
3
and  $$\Delta $$U
1
= $$\Delta $$U
2
= $$\Delta $$U
3

Answer

Q
3
> Q
2
> Q
1
and  $$\Delta $$U
1
= $$\Delta $$U
2
= $$\Delta $$U
3

Answer

Q
1
= Q
2
= Q
3
and  $$\Delta $$U
1
> $$\Delta $$U
2
> $$\Delta $$U
3

Answer

Q
3
= Q
2
= Q
1
and  $$\Delta $$U
1
> $$\Delta $$U
2
> $$\Delta $$U
3

Thermodynamics & KTG

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