Question 938: Thermodynamics & KTG

Question

The volume (V) of a monatomic
gas varies with its temperature
(T), as shown in the graph. The
ratio of work done by the gas,
to the heat absorbed by it, when
it undergoes a change from state
A to state B, is
![](https://neetcare-image.cdn.examgoal.net/1qpqahkka6tmkur/16f4ee03-143c-44aa-a763-b99072ca2f71/8ea8a630-95e8-11ea-aedc-f1c8d8e0194b/file-1qpqahkka6tmkus-289w.png)

Accepted Answer

Gas is monatomic, so C
p
= ${5 \over 2}R$
Given process is isobaric.
$ 	herefore $ dQ = nC
p
dT
or dQ = n$\left( {{5 \over 2}R} ight)$dT
Also, dW = PdV = nRdT ($ \because $ PV = nRT)
$ 	herefore $ Required ratio = ${{dW} \over {dQ}}$ = ${{nRdT} \over {n\left( {{5 \over 2}R} ight)dT}}$ = ${2 \over 5}$

Answer

${2 \over 5}$

Answer

${2 \over 3}$

Answer

${1 \over 3}$

Answer

${2 \over 7}$

Thermodynamics & KTG

The volume (V) of a monatomic gas varies with its temperature (T), as shown in the graph. The ratio of work done by the gas, to the heat absorbed by it, when it undergoes a change from state A to state B, is

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