Question 951: Thermodynamics & KTG

Question

One mole of an ideal diatomic gas undergoes a transition from A to B along a path AB as shown in the figure.
The change in internal energy of the gas during the transition is
![](https://neetcare-image.cdn.examgoal.net/1qpq2yck7l5m957/9d412514-4413-43d2-9d82-a683c588fce9/c61e60c0-6265-11ea-bddc-5f310cab17d0/file-1qpq2yck7l5m958-361w.jpg)

Accepted Answer

Change in internal energy from A $ 	o $ B
$\Delta U = {f \over 2}nR\Delta T = {f \over 2}nR\left( {{T_f} - {T_i}} ight)$
$ = {5 \over 2}\left\{ {{P_f}{V_f} - {P_i}{V_i}} ight\}$
(As gas is diatomic $ 	herefore $ f = 5)
$ = {5 \over 2}\left\{ {2 	imes {{10}^3} 	imes 6 - 5 	imes {{10}^3} 	imes 4} ight\}$
$ = {5 \over 2}\left\{ {12 - 20} ight\} 	imes {10^3}J = 5 	imes \left( { - 4} ight) 	imes {10^3}J$
$ 	herefore \Delta U =  - 20\,KJ$

Answer

20 J

Answer

$-$ 12 kJ

Answer

20 kJ

Answer

$-$ 20 kJ

Thermodynamics & KTG

One mole of an ideal diatomic gas undergoes a transition from A to B along a path AB as shown in the figure. The change in internal energy of the gas during the transition is

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